The
thermodynamics and other properties of the solutions of non-electrolytes can be
adequately expressed in terms of their concentrations, even at moderate concentrations.
But the solutions of electrolytes exhibit marked derivation even at relatively
low concentrations. Dilute ionic solutions have a concentration of 0.001 m or
even less. According to Debye's huckle theory of interionic attraction, the
electrostatic attractions between ions in the solution of an electrolyte have a significant influence on the mobility of ions. The ionic concentrations in case
of weak electrolytes, being low don’t show applicable derivations from the
ideal behavior. But in solutions of strong electrolytes, the ionic
concentrations are large, so interionic forces can’t be neglected. Due to
electrostatic attraction between in a fraction of cations and ions, the
solutions exhibit the properties of one in which the effective or apparent
concentrations of the ions are less than the theoretical concentrations
depending on the relative importance of factors, such as ion-ion
concentrations and ion solvent interactions, the effective concentrations of
the solute dissolved in water may appear to be less than, equal to or greater
than the molal concentration. This effect becomes more significant at higher
concentrations and increases the valance of the ions.
G.N
Lewis suggested due to restricted, mobility of the ions in solutions of strong
electrolytes the ions don’t exert their full effect for showing their behavior.
He proposed the term activity in place of concentration terms (molarity,
molality, mole fraction, formality). So as to explain the departure of
electrolytes solution from ideal behavior. To distinguished between the molar and
molal or formal of a substance in the effective concentration of an ion a
solution is called its activity. It is the customer to relate the activity of
a species to its concentration through the expression.
ai=
Ï’imi
in
which ai is the activity of
the substance I, Ï’i, is the activity coefficient of the substance
I, and mi is the molar concentration of the substance i. The activity coefficient(Ï’) is not a constant and its value varies with the concentration.
For aqueous solutions, both activity and concentration are expressed in the
same units, so that the activity coefficient is dimensionless. [For dilute
solutions, the molarity is almost numerically equal to molality, which is the preferred unit for colligative properties (because then the properties of the solutions don’t depend on the identity for the solutes). Therefore, we can
shift from molarity concentration units to molality concentration units].
For
dilute solutions (<0.001m), the electrostatic attractions can be neglected,
ai=
mi
and
the value of Ï’i becomes unity, For electrolytes, such as NaCl, The
activity of Na+ and Cl- ions can be written as
a+=
Ï’+ m+
and
a-=Ï’- m-
since
it isn’t possible to get only positive and negative ions in the solution of an electrolyte,
there is no experimental method available to determine the activity or activity
coefficient of individual ionic species. The reason is the solutions are
electrically neutral and we can’t increase the number of cations without an
equal increase in the number of anions. Since we can’t study relatively the
effects of cations and anions in the presence of each other in a neutral solution
is there for, it not possible to measure the individual ion activities.
Fortunately for more purposes, it is sufficient to know the means of ionic
activity(a±) and the mean activity coefficient (Ï’±).
Since
it is possible to substitute concentrations for activities in ionic solutions, it
is essential to consider how the ionic concentrations may be converted to the
activities and how such activities can be evaluated in order to introduce some definitions
commonly employed in dealing with activities of the strong electrolytes.
Consider an electrolyte AxBy which ionize in the solution
according to
Ax
By= XAz+ + yBz-
When Z+ and Z- are the
charges on the cation and anion respectively. the activity of the electrolyte
as a whole, a2, is defined in terms of the activities of the two
ions, a +and a - as
a2=ax+ay-
If
V is the total number of the ions furnished by one molecule of the electrolyte,
I. e V= x +y, then mean activity is
defined as
a±=(a2)1/v
=(ax+ay-)1/v
The
activities of the ions are related to their concentration through the relation.
a+= Ï’+m+
a.= Ï’-m.
Where
m+ and m- are the modalities of the cation and anions and
y and y are the corresponding activity coefficients. These activities
coefficients are appropriate factors that when multiplied by the modalities of
the respective ions yield their activities. introducing Eq (09 .06) and (9.67)
into Eq (9.64) . we obtain for as
a2=(m+
Ï’ +)X (m- Ï’ -) y
a2= (m+x my-)
(Ï’ x+ Ï’ y-)
and
for mean activity from Eq. (9.65)
a±=(a2)1/v
= ( m+xmy-) 1/v Ï’ x+ Ï’ y-)1/v3
the
factor
(mx+yy-)1/v
is defined as the mean molality of the electrolyte.
m±
=(m+xmy-)1/v
similarly
( Ï’
x+ Ï’ y-)1/v is
known as the mean activity coefficient.
Ï’ ±= ( Ï’ X+
Ï’ y-)1/v
in
term of mean molality and mean activity coefficient, Eq (9.68) and (9.69) may
be written as
a2 =ay±=m± y±
a±
= a21/v = (m± y± )v
finally since for any
electrolyte of molality m,we have
m+
= xm
m-=ym
Eqs.
(9.70) and (9.71) then take the form
a±(m
x+m-y)1/v Ï’±
=[ (xm)x ( ym)y ]1/v Ï’ ±
= [
(xx mx) (yymy) ] 1/v Ï’±
=[(xxyy)1/v
(mx+y) ] 1/v Ï’±
=[(xxyy)1/v
m Ï’±
and
a2=(a±)v=[(xxyy)1/vm
Ï’±]v
= (xxyy)mv
Ï’v±
equation
(9.72) and (9.73) are the expression needed for converting activities to modalities
or vice versa .thus for 1.1 electrolyte such as KCL,of molality
m,
we have x =1, y =1,v=2 and therefore.
a
±= ( 1x1) 1/2m Ï’±
a
2=a2± =m2y2±
again
for an electrolyte of the 2:1 type, such as BaCl2 we have c=1,y=2 and V= 3
a±=(1x22)
1/3 m Ï’±
=
(4)1/3m Ï’±
a2=a3±=4m3
Ï’3±
Example
9.5.
calculate
the mean and total activity of the following electrolytes
(Ä°) CuSO4
(Ä°Ä°) Na3
PO 4
(Ä°Ä°Ä°)
Ca3
(PO4 )2
Solution:
(Ä°) CuS4 x=1,y=1,and
v=1+1=2
a± =(1x1) ½
m Ï’±
= m Ï’±
a2=
(a±)2=m2 Ï’2±
(Ä°Ä°) Na3PO4 X=3,Y=1,V=X+Y=4
a±=
(33x11)1/4m
Y ± = (27)1/4 mY±
a2=(a±)4
27 m 4 Y4±
(Ä°Ä°Ä°)
Ca3(PO4) 2X =3,Y=2,V=X+Y=3+2=5
a±=(3322)1/5
m Ï’± = (108) 1/5 m Ï’ ±
a2=108m5
Ï’5±
Example
9.6 calculate the mean activity of the ions and activity of the electrolyte in
0.1m Na Cl solution. the Ï’± is 0.778
m=0.1 and Ï’±=
0.778
a±=m Ï’±=0.1
x0.778=0.0778
a2=(a±)2=(0.0778)2=6.05x103
By: Muzalim Kahlid
The writer is a post-graduate student from the Chemistry Department University of Turbat
Kech Balochistan
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